C++ Program to Display Factors of a Number

In this tutorial we make a program to find all factors of an integer (entered by the user) using for loop and if statement.

To understand this example, you should have the knowledge of following C++ programming topics:

  • C++ for Loop
  • C++ if, if…else and Nested if…else

This program takes a positive integer from an user and displays all the factors of that number.

Example: Display all Factors of a Number

#include <iostream>
using namespace std;

int main()
    int n, i;

    cout << "Enter a positive integer: ";
    cin >> n;

    cout << "Factors of " << n << " are: " << endl;  
    for(i = 1; i <= n; ++i)
        if(n % i == 0)
            cout << i << endl;

    return 0;



Enter a positive integer: 60
Factors of 60 are: 1 2 3 4 5 6 12 15 20 30 60


In this program, an integer entered by user is stored in variable n.

Then, for loop is executed with an initial condition i = 1 and checked whether n is perfectly divisible by i or not. If n is perfectly divisible by i then, i will be the factor of n.

In each iteration, the value of i is updated (increased by 1).

This process goes until test condition i <= n becomes false,i.e., this program checks whether number entered by user is perfectly divisible by all numbers from 1 to n and all displays factors of that number.

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