C++ Program to Check Whether a character is Vowel or Consonant.

In this example, if…else statement is used to check whether an alphabet entered by the user is a vowel or a constant.

To understand this example, you should have the knowledge of following C++ programmingtopics:

Five alphabets a, e, i, o and u are known as vowels. All other alphabets except these 5 alphabets are known are consonants.

This program assumes that the user will always enter an alphabet.

Example: Check Vowel or a Consonant Manually

#include <iostream>
using namespace std;

int main()
    char c;
    int isLowercaseVowel, isUppercaseVowel;

    cout << "Enter an alphabet: ";
    cin >> c;

    // evaluates to 1 (true) if c is a lowercase vowel
    isLowercaseVowel = (c == 'a' || c == 'e' || c == 'i' || c == 'o' || c == 'u');

    // evaluates to 1 (true) if c is an uppercase vowel
    isUppercaseVowel = (c == 'A' || c == 'E' || c == 'I' || c == 'O' || c == 'U');

    // evaluates to 1 (true) if either isLowercaseVowel or isUppercaseVowel is true
    if (isLowercaseVowel || isUppercaseVowel)
        cout << c << " is a vowel.";
        cout << c << " is a consonant.";

    return 0;



Enter an alphabet: u
u is a vowel.


The character entered by the user is stored in variable c.

The isLowerCaseVowel evaluates to true if c is a lowercase vowel and false for any other character.

Similarly, isUpperCaseVowel evaluates to true if c is an uppercase vowel and false for any other character.

If both isLowercaseVowel and isUppercaseVowel is true, the character entered is a vowel , if not the character is a consonant.

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